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TS EAMCET 5 May 2018 Shift 1 Solved Paper
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© examsnet.com
Question : 22
Total: 160
Consider a point object situated at a distance of 30 cm from the centre of sphere of radius 2 cm and refractive index 1.5 as shown in the figure. If the refractive index of the region surrounding this sphere is 1.4. the position of the image due to refraction by sphere with respect to the centre is
30 cm
45 cm
∞
28 cm
Validate
Solution:
Taking
n
1
=
1.4
and
n
2
=
1.5
For first surface
u
=
−
30
c
m
R
=
+
2
c
m
n
2
v
−
n
1
u
=
n
2
−
n
1
R
1.4
v
−
1.5
(
−
30
)
=
1.4
−
1.5
2
v
=
∞
For second surface
n
2
v
−
n
1
u
=
n
2
−
n
1
R
1.5
v
−
1.4
∞
=
1.4
−
1.5
2
v
=
+
30
c
m
© examsnet.com
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