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TS EAMCET 5 May 2018 Shift 2 Solved Paper
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© examsnet.com
Question : 118
Total: 160
Determine
V
CE
in the following silicon based transistor circuit
6.8 V
2.0 V
5.9 V
2.4 V
Validate
Solution:
Consider the following circuit.
Use KVL to the circuit.
V
C
C
=
i
C
R
C
+
V
C
E
+
i
E
R
E
V
C
C
=
i
C
R
C
+
V
C
E
+
i
C
R
E
(
∵
i
E
≈
i
C
)
V
C
E
=
V
C
C
−
i
C
(
R
C
+
R
E
)
…… (1)
Calculate the current
i
1
by ohm's law.
i
1
=
V
C
C
R
1
+
R
2
=
10
V
15
k
Ω
=
2
3
m
A
The value of
V
2
is calculated as follows.
V
2
=
i
1
R
2
=
2
3
m
A
×
5
k
Ω
=
10
3
=
3.3
V
Apply KVL to base circuit to obtain,
V
2
=
V
B
E
+
i
E
R
E
i
E
=
V
2
−
V
B
E
R
E
=
3.3
−
0.7
526
=
5
m
A
Therefore, from equation (1)
V
C
E
is calculated as,
V
C
E
=
V
C
C
−
i
C
(
R
C
+
R
E
)
=
10
−
5
m
A
(
1
k
Ω
+
526
Ω
)
=
2.4
V
© examsnet.com
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