Given that, Terminal velocity of rain, v=2m∕s Height, h=100cm=1m Surface area, A=1m2 Volume, V=Ah=1m3 Density of water, ρ=103kgm−3 Mass of water (rain), m=Vρ=103kg Now, energy transferred by rain per unit area =
Kinetic energy
Area
=
1
2
mv2
1
=
1
2
mv2=
1
2
×103×(2)2 =2×103J∕m2 Hence, energy transferred by rain to each square metre is 2×103J.