The horizontal displacement in second is, sx=(ucosθ)t =2√2cos45×2 =4m The vertical displacement in 2 second is, sy=usinθ+
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2
gt2 sy=2√2sin45°+
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(10)(2)2 sy=−16m The net displacement in 2 second is, s=√sx2+sy2 s=√42+(−16)2 s=16.49m The average velocity in the first 2 seconds can be calculated by, vavg=
