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TS EAMCET 9-Sep-2020 Shift 1 Solved Paper
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© examsnet.com
Question : 100
Total: 160
Two vessels separately contain two ideal gases A and B at the same temperature. The pressure of gas A is three times the pressure of gas B. Under these conditions, the density of gas A is found to be two times the density of B. The ratio of molecular weights of gas A and B, i.e.
M
A
M
B
is
2
3
3
2
3
4
4
3
Validate
Solution:
We are given with following condition,
Let
n
A
and
n
B
are the number of moles of gases in vessel
A
and vessel
B
respectively, then by gas equation, we have
p
A
V
A
=
n
A
R
T
A
and
p
B
V
B
=
n
B
R
T
B
but given
T
A
=
T
B
⇒
p
A
V
A
n
A
=
p
B
V
B
n
B
⇒
p
A
V
A
m
A
/
M
A
=
p
B
V
B
m
B
/
M
B
[
As, number of moles
=
mass of gas
molar mass
]
⇒
p
A
M
A
ρ
A
=
p
B
M
B
ρ
B
[
∵
m
V
=
ρ
=
density
]
Subtituting values, we have
3
p
⋅
M
A
2
p
=
p
⋅
M
B
ρ
⇒
M
A
M
B
=
2
3
© examsnet.com
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