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TS ICET 23 May 2018 Shift 2 Paper
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© examsnet.com
Question : 139
Total: 200
A point ( x,y) is equidistant from the points (7,1) and (3,5) then
(x - y) =
5
4
3
2
Validate
Solution:
Let P(x, y), A (7, 1), B(3, 5) be three points
Given PA = PB.
(
x
−
7
)
2
+
(
y
−
1
)
2
=
(
x
−
3
)
2
+
(
y
−
5
)
2
⇒
x
2
−
14
x
+
49
+
y
2
−
2
y
+
1
=
x
2
−
6
x
+
9
+
y
2
−
10
y
+
25
⇒
−
8
x
+
8
y
=
34
−
50
⇒
−
8
(
x
−
y
)
=
−
16
⇒
x
−
=
2
© examsnet.com
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