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Coding and Decoding Problems
Rule : The i th the letter is coded as thej th letter where j = 3i+ 2 (mod 26). The reverse process is followed for decoding.
Example : The 9th letter I is coded as C because. 3 × 9 + 2 (mod 26) is 29 (mod 26) which is 3 and the letter C is numbered as 3. Based on this coding procedure answer the questions 56 to 60.
Directions for questions 56 to 60 :
The letters A, B, C........Z of the English Alphabet are numbered 1, 2........... 26 respectively. A Code is designed by the following rule:Rule : The i th the letter is coded as the
Example : The 9th letter I is coded as C because. 3 × 9 + 2 (mod 26) is 29 (mod 26) which is 3 and the letter C is numbered as 3. Based on this coding procedure answer the questions 56 to 60.
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