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UPSC 2013 CDS 2 Math Paper
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© examsnet.com
Question : 16
Total: 100
19
5
+
21
5
is divisible by
[2013 CDS-II]
10 only
20 only
both 10 and 20
neither 10 nor 20
Validate
Solution:
Remember:
x
+
y
n
=
(
x
+
y
)
(
x
n
−
1
−
x
n
−
2
y
+
x
n
−
3
y
2
−
.
.
.
+
y
n
−
1
)
when n is odd.
∴
19
5
+
21
5
is divisible by
(
19
+
21
)
i.e 40 which is divisible by both 10 and 20
© examsnet.com
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