HCF (a, b) = 1 ⇒ a and b have no common factor other than 1. HCF (a,c) = 1 ⇒a and c have no common factor other than 1. So, a and bc have no common factor other than 1. ⇒HCF of (a, bc) = 1 Trick: Take a = 2, b = 3, c = 5. Then HCF(2, 3) = 1 HCF(2, 5) = 1 ∴ HCF(2, 3×5) = HCF(2, 15) = 1