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UPSC 2013 CDS 2 Math Paper
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© examsnet.com
Question : 32
Total: 100
What is the last digit in
7
402
+
3
402
?
[2013 CDS-II]
0
4
8
None of these
Validate
Solution:
7
402
+
3
402
=
7
4
(
100
)
+
2
+
3
4
(
100
)
+
2
Unit digit of
7
4
(
100
)
+
2
is
1
×
7
2
=
1
×
49
=
9
Unit digit of
34
(
100
)
+
2
is
1
×
3
2
=
1
×
9
=
9
So, unit digit of
7
402
+
3
402
+
9
+
9
=
18
© examsnet.com
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