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UPSC 2014 CDS I Math Paper
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© examsnet.com
Question : 31
Total: 100
What is the HCF of
8
(
x
5
−
x
3
+
x
)
and
28
(
x
6
+
1
)
?
[2014 CDS-I]
4
(
x
4
−
x
2
+
1
)
2
(
x
4
−
x
2
+
1
)
(
x
4
−
x
2
+
1
)
None of the above
Validate
Solution:
8
(
x
5
−
x
3
+
x
)
=
2
3
×
x
(
x
4
−
x
2
+
1
)
28
(
x
6
+
1
)
=
2
2
×
7
[
(
x
2
)
3
+
1
]
=
2
3
×
7
×
(
x
2
+
1
)
(
x
4
−
x
2
+
1
)
Therefore, the required HCF
=
2
2
×
(
x
4
−
x
2
+
1
)
(
x
4
−
x
2
+
1
)
© examsnet.com
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