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UPSC 2014 CDS II Math Paper
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© examsnet.com
Question : 15
Total: 100
If the side of a cube is increased by 100%, then by what percentage is the surface area of the cube increased?
[2014 CDS-II]
150%
200%
300%
400%
Validate
Solution:
Let the side of the original cube = a units
Surface area of the original cube
=
6
a
2
square units
Side of the new cube
=
a
+
100
100
×
a
=
2
a
units
Surface area of the new cube
=
6
(
2
a
2
)
=
24
a
2
square units
∴ % Increase in the surface area
=
(
24
a
2
−
6
a
2
6
a
2
)
×
100
%
=
300
%
Trick :
By
x
+
y
+
x
y
100
, we get
100
+
100
+
100
×
100
100
=
300
%
© examsnet.com
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