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UPSC 2015 CDS I Math Paper
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© examsnet.com
Question : 29
Total: 100
A thief is noticed by a policeman from a distance of 200 m. The thief starts running and the policeman chases him. The thief and the policeman run at the speed of 10 km/hr and 11 km/hr respectively. What is the distance between them after 6 minutes?
[2015 CDS-I]
100 m
120 m
150 m
160 m
Validate
Solution:
Speed of the thief = 10 km/hr
=
10
×
5
18
=
25
9
m
s
Distance covered by the thief in 6 minutes
=
25
9
×
6
×
60
=
1000
m
Speed of the policeman = 11 km/hr
=
11
×
5
18
=
55
18
m
/
s
Distance covered by the policeman in 6 minutes
=
55
18
×
6
×
60
=
1100
m
Therefore, distance between them after 6 minutes
=
(
200
+
1000
)
−
1100
=
1200
−
1100
=
100
m
© examsnet.com
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