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UPSC 2015 CDS II Math Paper

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Question : 43

Total: 100

An aeroplane flying at a height of 3000 m passes vertically above another aeroplane at an instant when the angles of elevation of the two planes from some point on the ground are 60° and 45° respectively. Then the vertical distance between the two planes is

1000(√3−1) m
1000√3 m
1000(3−√3) m
3000√3 m

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