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UPSC 2015 CDS II Math Paper
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© examsnet.com
Question : 51
Total: 100
A pipe with square cross-section is supplying water to a cistern which was initially empty. The area of cross-section is 4
c
m
2
and the nozzle velocity of water is 40 m/s. The dimensions, of the cistern are 10 m x 8 m x 6 m. Then the cistern will be full in
[2015 CDS-II]
9.5 hours
9 hours
8 hours 20 minutes
8 hours
Validate
Solution:
Let the cistern will be full in t seconds.
∴
t
=
(
Volume ofthe cistern
)
(
Volume of the water flowing out of the pipe per second
)
=
10
×
8
×
6
(
4
10000
×
40
)
=
30000
seconds
=
30000
3600
=
8
h
+
1
3
h
=
8
h
+
1
3
×
60
min
= 8 hours 20 minutes
© examsnet.com
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