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UPSC 2015 CDS II Math Paper
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© examsnet.com
Question : 78
Total: 100
The area of a trapezium is 336
c
m
2
. If its parallel sides are in the ratio 5 : 7 and the perpendicular distance between them is 14 cm, then the smaller of the parallel sides is
[2015 CDS-II]
20 cm
22 cm
24 cm
26 cm
Validate
Solution:
Let the parallel sides of the trapezium be 5k and 7k
Area of the trapezium
=
1
2
× Sum of the parallel sides × Perpendiculardistance between the parallel sides
∴
1
2
×
(
5
k
+
7
k
)
×
14
=
336
⇒
84
k
=
365
⇒
k
=
4
Therefore, smaller of the parallel sides
=
5
×
4
=
20
c
m
© examsnet.com
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