Remember: The lengths of tangents drawn from an external point to a circle are equal.
∴ AC = CE ....(1) BD = DE ....(2) PB = PA =16 cm ∴ PA + PB = 32 cm ⇒(PC + AC) + (PD + BD) = 32cm ⇒ PC + (CE + DE) + PD = 32cm [Using (1) and (2)] ⇒PC + CD + PD = 32 cm Therefore, perimeter of ΔPCD = 32 cm