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UPSC 2016 CDS II Math Paper
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© examsnet.com
Question : 5
Total: 100
What would be the maximum value of Q in the equation
5P9 + 3R7 + 2QS = 1114 ?
[2016 CDS-II]
9
8
5
4
Validate
Solution:
1 2
5 P 9
3 R 7
+ 2 Q 8
–––––––––––
1 1 1 4
∴
P
+
Q
+
R
+
2
=
11
⇒
P
+
Q
+
R
=
9
For the maximum value of Q, P and R should take the values 0.
Thus, the maximum value of Q is 9.
© examsnet.com
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