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UPSC 2016 CDS II Math Paper
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© examsnet.com
Question : 51
Total: 100
The radius of the base and the height of a solid right circular cylinder are in the ratio 2 :3 and its volume is 1617
c
m
3.
What is the total surface area of the cylinder ?
[2016 CDS-II]
462
c
m
2
616
c
m
2
770
c
m
2
786
c
m
2
Validate
Solution:
Let the radius and height of the right circular cylinder be 2k cm and 3k cm, respectively.
∴
π
r
2
h
=
1617
c
m
2
⇒
22
7
×
4
k
2
×
3
k
=
1617
⇒
k
3
=
1617
×
7
22
×
12
=
(
7
2
)
2
⇒
k
=
7
2
Radius of the cylinder = 7 cm
Height of the cylinder
=
21
2
cm
∴Total surface area of the cylinder
=
2
π
r
(
r
+
h
)
=
2
×
22
7
×
7
×
(
7
+
21
2
)
=
770
c
m
2
© examsnet.com
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