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UPSC 2016 CDS II Math Paper
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© examsnet.com
Question : 74
Total: 100
Two men on either side of a tower 75 m high observe the angle of elevation of the top of the tower to be 30° and 60°. What is the distance between the two men ?
[2016 CDS-II]
100
√
3
m
75
√
3
m
100
√
3
3
m
60
√
3
m
Validate
Solution:
Let AB be the tower.
AB = 75 m
Suppose P and Q be the positions of the two men on either side of the tower.
In right ΔABQ,
tan
60
°
=
√
3
=
A
B
B
Q
⇒
B
Q
=
75
√
3
=
25
√
3
m
In right ΔABP,
tan
30
°
=
1
√
3
=
A
B
B
P
⇒
1
√
3
=
75
B
P
⇒
B
P
=
75
√
3
m
∴ Distance between the two men
=
P
Q
=
B
P
+
B
Q
=
75
√
3
+
25
√
3
=
100
√
3
m
© examsnet.com
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