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UPSC 2017 CDS II Math Paper
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© examsnet.com
Question : 60
Total: 100
What is the area of the triangle whose sides are 51 cm, 37 cm and 20 cm ?
[2017 CDS-II]
300 square cm
305 square cm
306 square cm
307 square cm
Validate
Solution:
Semi-perimeter of the triangle, s
=
51
+
37
+
20
2
=
108
2
=
54
c
m
Therefore, area of the triangle
=
√
s
(
s
−
a
)
(
s
−
b
)
(
s
−
c
)
=
√
54
(
54
−
51
)
(
54
−
37
)
(
54
−
20
)
=
√
54
×
3
×
17
×
34
=
306
c
m
2
© examsnet.com
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