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UPSC 2017 CDS II Math Paper
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© examsnet.com
Question : 74
Total: 100
From a solid cylinder whose height is 8 cm and of base radius 6 cm, a conical cavity of height 8 cm and of base radius 6 cm is formed by hollowing out. What is the inner surface area of the cavity ?
[2017 CDS-II]
6π square cm
8π square cm
10π square cm
60π square cm
Validate
Solution:
Height of the cylinder = Height of the cone = h = 8 cm
Radius of the cylinder = Radius ofthe cone = r = 6 cm
Slant height of the cone = l
=
√
r
2
+
h
2
=
√
6
2
+
8
2
=
√
100
=
10
c
m
Therefore, inner surface area of the cavity
=
π
×
r
×
l
=
π
×
6
×
10
=
60
π
square cm
© examsnet.com
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