In ΔABC, BE is the median. Therefore, E is the mid-point of AC. ⇒AE=EC=
AC
2
...(1) Also, AD is the median. So, D is the mid-point of BC. In ΔBCE D is the mid-point of BC and DF||BE. Therefore, F is the mid-point of EC. (Converse of mid-point theorem) ⇒CF=EF=