Tips & Tricks GIVEN: Ashok gets 26% marks in an examination but fails by 12 marks. Arush gets 43% marks which is 39 more than the passing marks. FORMULA USED: X% of a number Y = Y × X/100 If a number ‘Y’ is increased by X%, increased number = Y × (1 + X/100) CALCULATION: From the given statement, Difference of marks of Arush and Ashok = 39 + 12 = 51 Let ‘x’ be the maximum marks of the examination. So, 43% of x – 26% of x = 51 ⇒ 17% of x = 51 ⇒ x = 300 ∴ Maximum marks of the examination = 300 Smart Trick Difference in both marks = 51 Difference both percentages = 43% - 26% = 17% Now, 17% = 51 ⇒ 1% = 3 ∴ 100% = 300