GIVEN: x + y < 20 CALCULATION: 3x + 5y = 81 3x = 81 – 5y To get integer value of ‘x’ value of ‘y’ must be a multiple of 3. Let y = 3; x = 22 => x + y = 25 [Invalid] Let y = 6; x = 17 => x + y = 23 [Invalid] Let y = 9; x = 12 => x + y = 21 [Invalid] Let y = 12; x = 7 => x + y = 19 [Valid] Let y = 15; x = 2 => x + y = 17 [Valid] ∴ 2 possible solutions are there.