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UPSC CDS 1 2021 Math Paper
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© examsnet.com
Question : 6
Total: 100
What is the least value of
3
sin
2
θ
+
4
cos
2
θ
?
5
4
3
2
Validate
Solution:
👈: Video Solution
we have
3
sin
2
θ
+
4
cos
2
θ
=
3
(
sin
2
θ
+
cos
2
θ
)
+
cos
2
θ
=
3
+
cos
2
θ
(
3
sin
2
θ
+
4
cos
2
θ
)
min
=
3
+
cos
2
θ
|
min
=
3
© examsnet.com
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