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UPSC CDS 1 2022 Math Paper
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© examsnet.com
Question : 41
Total: 100
If
x
=
9999
, then what is the value of the following?
4
x
3
−
x
(
2
x
+
1
)
(
6
x
−
3
)
1111
2222
3333
6666
Validate
Solution:
👈: Video Solution
Given:
x
=
9999
Formula Used:
a
2
−
b
2
=
(
a
−
b
)
(
a
+
b
)
Calculation:
To find
4
x
3
−
x
(
2
x
+
1
)
(
6
x
−
3
)
⇒
x
(
4
x
2
−
1
)
(
2
x
+
1
)
(
6
x
−
3
)
⇒
x
[
(
2
x
)
2
−
(
1
)
2
]
(
2
x
+
1
)
(
6
x
−
3
)
⇒
x
(
2
x
−
1
)
(
2
x
+
1
)
3
(
2
x
+
1
)
(
2
x
−
1
)
⇒
x
∕
3
⇒
9999
∕
3
=
3333
∴
The value of the expression at
x
=
9999
is 3333 .
© examsnet.com
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