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UPSC CDS 2 2018 Math Paper
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© examsnet.com
Question : 29
Total: 100
A cyclist covers his first 20 km at an average speed of 40 kmph, another 10 km at an average speed of 10 kmph and the last 30 km at an average speed of 40 kmph. Then the average speed of the entire journey is
[2018 CDS-II]
20 kmph
26.67 kmph
28.24 kmph
30 kmph
Validate
Solution:
(b) We know that, Time
=
Distance
Speed
Time taken by cyclist to cover first
20
k
m
=
20
40
=
1
2
h
Time taken by cyclist to cover
10
k
m
=
10
10
=
1
h
And time taken by cyclist to cover remaining
30
k
m
=
30
40
=
3
4
h
Now, total distance travelled
=
(
20
+
10
+
30
)
k
m
=
60
k
m
Total time taken
=
(
1
2
+
1
+
3
4
)
h
=
(
2
+
4
+
3
4
)
=
9
4
h
∴
Required average speed
=
60
9
×
4
=
80
3
k
m
∕
h
=
26.67
k
m
∕
h
© examsnet.com
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