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UPSC CDS 2 2018 Math Paper
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© examsnet.com
Question : 80
Total: 100
A rectangular block of length 20 cm, breadth 15 cm and height 10 cm is cut up into exact number of equal cubes. The least possible number of cubes will be
[2018 CDS-II]
12
16
20
24
Validate
Solution:
HCF of 20, 15 and 10 = 5
Side of cube of maximum volume= 5 m
Minimum possible number of cubes
=
20
×
15
×
10
5
×
5
×
5
=
24
Thus, 24 numbers of required cubes are possible.
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