given that abc=30;a,b and c are positive integer abc=30=1×1×30⇒ number of solution =
3!
2!
=3 abc=30=1×2×15⇒ number of solution =3!=6 abc=30=1×3×10⇒ number of solution =3!=6 abc=30=1×5×6⇒ number of solution =3!=6 abc=30=2×3×5⇒ number of solution =3!=6 Total number of solutions =3+6+6+6+6=27