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UPSC CDS 2 2021 Math Paper
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© examsnet.com
Question : 4
Total: 100
The minute hand of a clock is
21
c
m
long. What is the area on the face of the clock described by the minute hand between 10:10 am and 10:30 am? (take
π
=
22
7
)
231
c
m
2
331
c
m
2
462
c
m
2
492
c
m
2
Validate
Solution:
👈: Video Solution
Given, the length of minute hand of the clock
=
21
c
m
Time for calculating the area is 10:10 am to 10:30 am.
We know, the area of rhombus
=
1
2
(
d
1
×
d
2
)
Where,
d
1
and
d
2
are the lengths of the diagonals.
Therefore,
336
=
1
2
×
(
48
)
×
(length of other diagonal) The length of other diagonal
=
336
24
=
14
c
m
We know that, diagonals of rhombus bisect each other at right angle.
∵
A
O
=
1
2
×
14
=
7
c
m
and
B
O
=
1
2
×
48
=
24
c
m
∴
ln
△
A
B
O
,
A
B
2
=
O
A
2
+
O
B
2
A
B
2
=
7
2
+
24
2
A
B
=
√
49
+
576
=
25
c
m
.
Length of side of rhombus
=
25
c
m
Perimeter of rhombus
=
4
×
25
c
m
=
100
c
m
.
© examsnet.com
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