We know Total number of factors of xpyq is (p+1)(q+1) Number of odd factors of xpyqzr if x is even and y and z are odd then the factors are 1×(q+1)(r+1) We have, ⇒N=126×38×53 ⇒N=26×26×36×38×53 ⇒N=212×314×53 Total number of factors:- (12+1)×(14+1)×(3+1) Total number of factors:- 13×15×4 Total number of factors =780 Statement I: The number of odd factors of N is 60 . Number of odd factors =1×(14+1)×(3+1) Number of odd factors =1×15×4 A number of odd factors =60. Hence, Statement I is correct. Statement II: The number of even factors of N is 720 . Number of even factors = Total number of factors − Odd factors Number of even factors =780−60 Number of even factors =720 Hence, Statement II is correct. ∴ Both statements are correct.