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UPSC CDS I 2019 Math Paper
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© examsnet.com
Question : 13
Total: 100
It is given that
log
10
2 = 0.301 and
log
10
3 = 0.477. How many digits are there in
(
108
)
10
?
[2019 CDS-I]
19
20
21
22
Validate
Solution:
When Log(x) = abcde, then number of digits in x is a + 1.
log
10
108
10
=
10
log
10
(
2
2
×
3
3
)
=
10
(
log
10
2
2
+
log
10
3
3
)
=
20
log
10
2
+
30
log
10
3
=
20
×
0.301
+
30
×
0.477
=
20.33
Number of digits
=
20
+
1
=
21
© examsnet.com
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