a=b=c=2⇒a+b+c=6⇒2s=6⇒s=3 Then: s−a=s−b=s−c=1 Now evaluate: s(s−a)(s−b)(s−c)×[
1
s−a
+
1
s−b
+
1
s−c
−
1
s
] =3×1×1×1×[1∕1+1∕1+1∕1−1∕3] =3×(3−1∕3)=3×(8∕3)=8 Check which option gives 8: abc=2×2×2=8( Match ) 2abc=16( Not matching ) 4abc=32( Not matching ) ab+bc+ca=12( Not matching )
