Area of the field = Area of ΔABC + Area of ΔCDH + Area of rectangle AHDG + Area of trapezium DEFG Now, AC = AH + HC = 3 + 1 = 4 m Therefore, area of ΔABC
=√
9
2
×(
9
2
−2)×(
9
2
−3)×(
9
2
−4) =√
9
2
×
5
2
×
3
2
×
1
2
=
3
4
√15m2
Area of ΔCDH
=
1
2
×CH×Dh=
1
2
×3×2=3m2
Area of rectangle AHDG =HD×DG=2×1=2,m2 Area of trapezium DEFG =