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UPSC CDS Math Number System Questions
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© examsnet.com
Question : 53
Total: 102
What is the maximum value of m, if the number N = 90 x 42 x 324 x 55 is divisible by
3
m
?
[2016 CDS-I]
8
7
6
5
Validate
Solution:
N
=
90
×
42
×
324
×
55
=
9
×
10
×
3
×
14
×
81
×
4
×
55
⇒
3
2
×
10
×
3
×
14
×
3
4
×
4
×
55
=
3
7
×
10
×
14
×
4
×
55
Thus, the maximum value of m if N is divisible by
3
m
by 7.
© examsnet.com
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