ΔABC is an equilateral triangle with each side = 30 cm.
Since PX || AC ∴ ∠BXP =∠ XPB =60° Also XBP = 60° Let PX be x Then BP = x and BX = x Similarly, YQ = QC = YC = x Also in Δ AXY : AX=XY=AY=(30−x)cm Now, It is given that XY + XP + YQ = 40 ∴30−x+2x=40 ⇒x=10cm PQ=30–2x=30–2×10=10cm