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UPSC CDS Math Speed, Time and Distance Questions
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© examsnet.com
Question : 41
Total: 53
In a race of 100 m, A beats B by 4 m and A beats C by 2 m. By how many metres (approximately) would C beat B in another 100 m race assuming C and B run with their respective speeds as in the earlier race ?
[2015 CDS-II]
2
2.04
2.08
3.2
Validate
Solution:
Let A reaches the finish line after T seconds.
Therefore, Speed of A
v
A
=
100
T
m/s
Speed of B
=
v
B
=
100
−
4
T
=
96
T
m/s
Speed of C
=
v
C
=
100
−
2
T
=
98
T
m/s
Suppose C reaches the finish lineafter t seconds in another race and C beats B by x m.
Speed of B
=
v
B
=
100
−
x
t
m/s
Speed of C
=
v
C
=
100
t
m/s
∴
v
B
v
C
=
96
T
98
T
=
100
−
x
t
100
t
⇒
48
49
=
100
−
x
100
⇒
4800
=
4900
−
49
x
⇒
49
x
=
100
⇒
x
=
100
49
=
2.04
m (approx)
© examsnet.com
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