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UPSC CDS Math Triangles Questions
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© examsnet.com
Question : 10
Total: 68
A ladder is resting against a vertical wall and its bottom is 2.5 m away from the wall. If it slips 0.8 m down the wall, then its bottom will move away from the wall by 1.4 m. What is the length of the ladder ?
[2019 CDS-I]
6.2 m
6.5 m
6.8 m
7.5 m
Validate
Solution:
Let the length of the ladder be l metres.
(
0.8
+
x
)
2
+
2.52
=
l
2
x
2
+
(
2.5
+
1.4
)
2
=
l
2
Equating both the equations:
(
0.8
+
x
)
2
+
2.5
2
=
x
2
+
(
2.5
+
1.4
)
2
⇒
0.8
2
+
x
2
+
1.6
x
+
2.5
2
=
x
2
+
15.21
⇒
1.6
x
=
1.32
+
7
=
8.32
x
=
5.2
m
Length of ladder
√
(
0.8
+
5.2
)
2
+
2.5
2
=
√
42.25
=
6.5
m
© examsnet.com
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