In ΔABC and ΔDEF, ∠ABC = ∠ DEF(Given) ∠ACB = ∠DFE(Given) ∴ΔABC ~ ΔDEF (AA Similarity) ⇒
AB
DE
=
BC
EF
(Corresponding sides are proportional) ⇒
AB
DE
=
2BL
2EM
⇒
AB
DE
=
BL
EM
In ΔABL and ΔDEM
AB
DE
=
BL
EM
∠ABC = ∠BEF (Given) ∴ Δ ABL ~ ΔDEM (SAS Similarity) Hence, statement I is true Remember:If two triangles are congruent, then their corresponding sides are equal. Therefore, ΔALC is not congruent to ΔDMF if AC ≠ DF. Hence, statement II is false.