Hence, statement (1) is incorrect. We know that −1≤sinx≤1 Also, 0≤sin2x≤1⇒1≤3sin2x≤3 The given equation holds good if sinx=1 and 3sin2x=1.But, there exists no value of x for which sinx=1 and 3sin2x=1 simultaneously. Thus, the given equation does not hold good for any real x. Hence, statement (2) is correct