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UPSC NDA 2 2012 Mathematics Paper
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© examsnet.com
Question : 42
Total: 120
The equation of the locus of a point which is always equidistant from the points
(
1
,
0
)
and
(
0
,
−
2
)
is :
2
x
+
4
y
+
3
=
0
4
x
+
2
y
+
3
=
0
2
x
+
4
y
−
3
=
0
4
x
+
2
y
−
3
=
0
Validate
Solution:
AC
2
=
BC
2
⇒
(
x
−
1
)
2
+
(
y
−
0
)
2
=
(
x
−
0
)
2
+
(
y
+
2
)
2
⇒
x
2
−
2
x
+
1
+
y
2
=
x
2
+
y
2
+
4
y
+
4
−
2
x
−
4
y
−
3
=
0
⇒
2
x
+
4
y
+
3
=
0
© examsnet.com
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