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UPSC NDA 2 2012 Mathematics Paper
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© examsnet.com
Question : 58
Total: 120
What is the equation to the plane through
(
1
,
2
,
3
)
parallel to
3
x
+
4
y
−
5
z
=
0
?
3
x
+
4
y
+
5
z
+
4
=
0
3
x
+
4
y
−
5
z
+
14
=
0
3
x
+
4
y
−
5
z
+
4
=
0
3
x
+
4
y
−
5
z
−
4
=
0
Validate
Solution:
Let equation of plane parallel to
3
x
+
4
y
−
5
z
=
0
is
3
x
+
4
y
−
5
z
+
λ
=
0
∵
it passes through
(
1
,
2
,
3
)
∴
3
(
1
)
+
4
(
2
)
−
5
(
3
)
+
λ
=
0
⇒
3
+
8
−
15
+
λ
=
0
⇒
λ
=
4
∴
equation of plane is
3
x
+
4
y
−
5
z
+
4
=
0
.
© examsnet.com
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