Concept:The absolute value function splits the integral at the point where the expression inside changes sign.Explanation:The critical point of ∣1−x4∣ on [1,3] is x=1, where 1−x4=0.For x≥1, 1−x4≤0, so ∣1−x4∣=−(1−x4)=x4−1.Therefore, I=∫13∣1−x4∣dx=∫13(x4−1)dx.Integrate: ∫(x4−1)dx=5x5−x.Evaluate from 1 to 3: (535−3)−(515−1)=(5243−515)−(51−55)=5228−(−54)=5232.Answer:5232 (Option D).