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UPSC NDA 2 2016 Mathematics Solved Paper
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© examsnet.com
Question : 25
Total: 120
If
m
=
[
1
0
0
1
]
and
n
=
[
0
1
−
1
0
]
then what is the value of the determinant of
m
cos
θ
−
n
sin
θ
[NDA II 2016]
- 1
0
1
2
Validate
Solution:
m
cos
θ
−
n
sin
θ
=
[
cos
θ
0
0
cos
θ
]
−
[
0
sin
θ
−
sin
θ
0
]
=
[
cos
θ
−
sin
θ
sin
θ
cos
θ
]
det.
(
m
cos
θ
−
n
sin
θ
)
=
cos
2
θ
−
(
−
sin
2
θ
)
=
cos
2
θ
+
sin
2
θ
=
1
© examsnet.com
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