Concept:Use the formula dxdax=axlna and the property ∫f(x)f′(x)dx=ln∣f(x)∣+C.Explanation:We have f(x)=2x.Then f′(x)=2xln2.Therefore, f(x)f′(x)=2x2xln2=ln2.Now integrate: ∫210f(x)f′(x)dx=∫210ln2dx.Since ln2 is a constant, ∫210ln2dx=ln2[x]210=ln2(10−2)=8ln2.Answer:8ln2 (Option D).