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UPSC NDA 2 2022 Mathematics Solved Paper

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Consider the following for the next three (03) items that follow:

Let

z=\;\frac{1+i \sin \theta}{1-i \sin \theta}

where

i=\sqrt{-1}

[NDA II 2022]

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Question : 16 of 120

Marks: +1, -0

What is the modulus of

z

1
$\sqrt{2}$
$1+\sin^{2}\theta$
$\;\frac{1+\sin^{2}\theta}{1-\sin^{2}\theta}$

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