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UPSC NDA 2 2022 Mathematics Solved Paper

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Consider the following for the next three (03) items that follow:
Let A=(0sin2θcos2θcos2θ0sin2θsin2θcos2θ0)A=\begin{pmatrix} 0 & \sin^2 \theta & \cos^2 \theta \\ \cos^2 \theta & 0 & \sin^2 \theta \\ \sin^2 \theta & \cos^2 \theta & 0 \end{pmatrix} and A=P+QA=P+Q where PP is symmetric matrix and QQ is skew-symmetric matrix.
[NDA II 2022]
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