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UPSC NDA 2 2022 Mathematics Solved Paper

Question Numbers: 43-45

There are two points P and Q due south of a leaning tower, which leans towards north. P is at a distance x and Q is at distance y from the foot of the tower (x > y). The angles of elevation of the top of the tower from P and Q are 15° and 75° respectively.

Question : 44 of 120

Marks: +1, -0

If θ is the inclination of the tower to the horizontal, then what is cot θ equal to ?

2 + $\frac{\sqrt{3}(\text{x-y})}{\text{x+y}}$
2 − $\frac{\sqrt{3}(\text{x-y})}{\text{x+y}}$
2 + $\frac{\sqrt{3}(\text{x+y})}{\text{x-y}}$
2 − $\frac{\sqrt{3}(\text{x+y})}{\text{x-y}}$

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