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UPSC NDA I 2011 Mathematics Paper
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© examsnet.com
Question : 96
Total: 120
If
A
,
B
,
C
are in AP and
b
:
c
=
√
3
:
√
2
, then what is the value of
sin
C
?
1
1
√
3
√
3
1
√
2
Validate
Solution:
Since
A
+
B
+
C
=
180
∘
Also
2
B
=
A
+
C
⇒
2
B
+
B
=
180
∘
⇒
B
=
60
∘
Now
b
sin
B
=
c
sin
C
⇒
b
C
=
sin
B
sin
C
⇒
√
3
√
2
=
sin
60
∘
sin
C
⇒
sin
C
=
sin
60
∘
×
√
2
√
3
=
√
3
2
×
√
2
√
3
⇒
sin
C
=
1
√
2
.
© examsnet.com
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